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7k^2+48k+36=0
a = 7; b = 48; c = +36;
Δ = b2-4ac
Δ = 482-4·7·36
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-36}{2*7}=\frac{-84}{14} =-6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+36}{2*7}=\frac{-12}{14} =-6/7 $
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